How about 40 and 1.
The two numbers can be 5 times 8 = 40
The numbers will be the square root of 1120
260
They are 40 and 40
There are no two real numbers that do. Using complex numbers, these two do: (-3/2 + i√151/2) & (-3/2 - i√151/2) Two numbers that add to -3 and multiply to -40 are -8 & 5 Two numbers that add to 3 and multiply to -40 are 8 & -5 Two complex numbers that add to 3 and multiply to 40 are (3/2 + i√151/2) & (3/2 - i√151/2)
27
-34
-452
The two numbers that add to -6 and multiply to -40 are -10 and 4. This is because -10 + 4 = -6 and -10 * 4 = -40. This type of problem can be solved by setting up a system of equations where the sum of the numbers is -6 and the product of the numbers is -40, then solving for the two numbers.
51
There are no two real numbers that both multiply to give 25 and add to make 40. The two numbers would have to satisfy the equations ( x \times y = 25 ) and ( x + y = 40 ). However, solving these equations leads to a contradiction, as the maximum possible sum of two positive numbers that multiply to 25 is less than 40.
-43