i do not get what you mean
-Vipsa
Multiply the two numbers. 3.5 times 560=
HCF is the highest common factor of two or more numbers. HCf of 260 and 560 is 20.
Consecutive numbers implies integers. Rational or real numbers are infinitely dense so there is no "next" number. There can be no pairs of integers such that their product is a fractional number between 559 and 560.
There are many possible options. A simple answer is 1 and 560.
To determine how many 8s can go into 560, you divide 560 by 8. Performing the calculation, 560 ÷ 8 equals 70. Therefore, 70 eights can go into 560.
56
They are: 2*2*2*2*5*7 = 560
There is only one: 560.Otherwise, you have sets of numberS that add up to 560. And there are infinitely many sets.For example: 1 + 1 +1 + 1 ... 560 timesor 1 + 1 + 1 + ... 558 times + 0.9 + 1.1or 1 + 1 + 1 + ... 558 times + 0.8 + 1.2etc
There are infinite numbers, but a fine example is just 7*8*10 or 560
The factor pairs of 560 are: 1 × 560 2 × 280 4 × 140 5 × 112 7 × 80 8 × 70 10 × 56 14 × 40 16 × 35 20 × 28
560
560 ÷ 16 = 35