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x+y=3 xy=4 so x(3-x)=3 3x-x^2-3=0 so x^2-3x+3=0 We can't factor this, so we use the quadratic equation 3+ or - Square root (9-12) all divided by 2 Since square root of 9-12 is negative, the solutions are NOT real There are no real numbers that satisfy these conditions.
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