x+y=3 xy=4 so x(3-x)=3 3x-x^2-3=0 so x^2-3x+3=0 We can't factor this, so we use the quadratic equation 3+ or - Square root (9-12) all divided by 2 Since square root of 9-12 is negative, the solutions are NOT real There are no real numbers that satisfy these conditions.
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∙ 15y agoIf the product of two numbers is 4.2 and their sum is 4.4. then the numbers are 3 and 1.4.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
3 and 12
12 and 3
3 and 7
If the product of two numbers is 4.2 and their sum is 4.4. then the numbers are 3 and 1.4.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
3 & 15
3 and 12
12 and 3
3 and 7
-8 and -3 have a sum of -11 and product of 24
3 & 3
3 and 6, Sum, 3 + 6 = 9 Product, 3 x 6 = 18
15 and 3
The numbers are: 3 and 12
Not possible in whole numbers