x+y=3 xy=4 so x(3-x)=3 3x-x^2-3=0 so x^2-3x+3=0 We can't factor this, so we use the quadratic equation 3+ or - Square root (9-12) all divided by 2 Since square root of 9-12 is negative, the solutions are NOT real There are no real numbers that satisfy these conditions.
If the product of two numbers is 4.2 and their sum is 4.4. then the numbers are 3 and 1.4.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
3 and 7
3 and 12
12 and 3
If the product of two numbers is 4.2 and their sum is 4.4. then the numbers are 3 and 1.4.
17 and 3 are two prime numbers whose sum is 20. Their product is 51.
3 & 15
3 and 7
3 and 12
12 and 3
3 & 3
-8 and -3 have a sum of -11 and product of 24
3 and 6, Sum, 3 + 6 = 9 Product, 3 x 6 = 18
15 and 3
Not possible in whole numbers
They are 2 and 3