Q: What two square roots are used to estimate square root 43?

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Square root 64 and square root 81

The square root of 36 and the square root of 49.

Square root of 64 and square root of 81, perhaps.

The square root of eight is in between the square root of 7 and the square root of 9, which equals 3.

The square root of 36 is 6 and the square root of 49 is 7 These are used as 42 is between 36 and 49.

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Square root 64 and square root 81

The square root of 36 and the square root of 49.

Square root of 64 and square root of 81, perhaps.

The square root of eight is in between the square root of 7 and the square root of 9, which equals 3.

The square root of 36 is 6 and the square root of 49 is 7 These are used as 42 is between 36 and 49.

The two square roots used are 2 and 3, since 2 and 3 squared are 4 and 9, respectively. Since 5 is between 4 and 9, we can deduce that the square root of 5 is between 2 and 3.

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.

If you have a square root of a number, that means that your "square root" squared (multiplied by itself) will give you your original number. For example: * The square root of 4 is 2. * 2 x 2 is 4.

Of course not. 3 squared is 9, the square root of 9 is 3.

This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.