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+6.5 and -6.5, possibly.

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13y ago

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Which two square roots are used to estimate square root 67?

Square root 64 and square root 81


Which two square roots are used to estimate the square root of 43?

The square root of 36 and the square root of 49.


What two square roots are used to estimate the square root of 67?

Square root of 64 and square root of 81, perhaps.


Which two square roots are used to estimate the square root of 8?

The square root of eight is in between the square root of 7 and the square root of 9, which equals 3.


Which two square roots are used to estimate the square root of 42?

The square root of 36 is 6 and the square root of 49 is 7 These are used as 42 is between 36 and 49.


What two square roots are used to estimate the square root of 5?

The two square roots used are 2 and 3, since 2 and 3 squared are 4 and 9, respectively. Since 5 is between 4 and 9, we can deduce that the square root of 5 is between 2 and 3.


What is the square root of four?

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.


What is the square root of negative four?

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.


What is the square root of minus 4?

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.


What are square roots used for?

If you have a square root of a number, that means that your "square root" squared (multiplied by itself) will give you your original number. For example: * The square root of 4 is 2. * 2 x 2 is 4.


Are squares and square roots the same thing?

Of course not. 3 squared is 9, the square root of 9 is 3.


What is the conjugate of a denominator?

This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.

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