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Square root of 64 and square root of 81, perhaps.

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Q: What two square roots are used to estimate the square root of 67?

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Square root 64 and square root 81

The square root of 36 and the square root of 49.

The square root of eight is in between the square root of 7 and the square root of 9, which equals 3.

+6.5 and -6.5, possibly.

The square root of 36 is 6 and the square root of 49 is 7 These are used as 42 is between 36 and 49.

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The square root of 36 and the square root of 49.

Square root 64 and square root 81

The square root of eight is in between the square root of 7 and the square root of 9, which equals 3.

+6.5 and -6.5, possibly.

The square root of 36 is 6 and the square root of 49 is 7 These are used as 42 is between 36 and 49.

The two square roots used are 2 and 3, since 2 and 3 squared are 4 and 9, respectively. Since 5 is between 4 and 9, we can deduce that the square root of 5 is between 2 and 3.

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.

The answer is 2i. When dealing with negative square roots, the expression i is used to represent the square root of -1.

If you have a square root of a number, that means that your "square root" squared (multiplied by itself) will give you your original number. For example: * The square root of 4 is 2. * 2 x 2 is 4.

Of course not. 3 squared is 9, the square root of 9 is 3.

This is related to the technique used to eliminate square roots from the denominator. If, for example, the denominator is 4 + root(3), you multiply both numerator and denominator by 4 - root(3). In this case, "4 - root(3)" is said to be the "conjugate" of "4 + root(3)". When doing this, there will be no more square roots in the denominator - but of course, you'll instead have a square root in the numerator.