It is a combusion.It generates water and CO2
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
Take the balanced equation. CH4+2O2---->CO2+2H2O.So 2.8mol of CH4 need 5.6mol of O2.So O2 is limitting factor
The combustion of a hydrocarbon yields carbon dioxide and water. CH4 + 2O2 ---> CO2 + 2H2O
O2
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.
Assuming complete combustion: CH4 + 2O2 --> 2H2O + CO2.
Burning, oxidation.
Take the balanced equation. CH4+2O2---->CO2+2H2O.So 2.8mol of CH4 need 5.6mol of O2.So O2 is limitting factor
Make sure atoms on both sides are equal.Balanced equation as follows. CH4+2O2---->CO2+2H2O
The combustion of a hydrocarbon yields carbon dioxide and water. CH4 + 2O2 ---> CO2 + 2H2O
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
Unbalanced CH4 + O2 = H2O + CO2 Balanced CH4 + 2O2 = 2H20 + CO2
This equation is CH4 + 2 O2 => CO2 + 2 H2O.