It is a combusion.It generates water and CO2
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
To determine the limiting reagent, we need to compare the amount of each reactant to their stoichiometric coefficients in the balanced equation. The balanced equation for the combustion of CH4 with O2 is: CH4 + 2O2 -> CO2 + 2H2O. From the given amounts, we can see that O2 is in excess, so CH4 is the limiting reagent.
The given equation represents a combustion reaction, where methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). The release of 218 kcal indicates that this reaction is exothermic, releasing heat energy.
The molecular equation for the combustion of methane gas (CH4) in the presence of oxygen (O2) is: CH4 + 2O2 -> CO2 + 2H2O.
The balanced equation is: CH4 + 2 O2 → CO2 + 2 H2O
The combustion of methane can be balanced in the following manner. One molecule of CH4 plus two molecules of O2 produces one molecule of CO2 plus one molecule of H2O.
CH4+O2 --- CO2+H2O... All that's missing - is the number 2 before the water molecule... CH4+O2 --- CO2+2H2O
The chemical reaction is: CH4 + 2O2 --> 2H2O + CO2 CO2 is the carbon dioxide.
Burning, oxidation.
To determine the limiting reagent, we need to compare the amount of each reactant to their stoichiometric coefficients in the balanced equation. The balanced equation for the combustion of CH4 with O2 is: CH4 + 2O2 -> CO2 + 2H2O. From the given amounts, we can see that O2 is in excess, so CH4 is the limiting reagent.
The balanced chemical equation for the reaction CH4 + 2O2 → CO2 + 2H2O shows that 1 molecule of CH4 reacts with 2 molecules of O2 to produce 1 molecule of CO2 and 2 molecules of H2O. This equation ensures that the number of atoms of each element is the same on both sides of the reaction arrow.
I assume you were looking to balance the reaction: CH4 + 2O2 --> CO2 +2H2O
The balanced chemical equation for methane (CH4) burning in air (O2) is: CH4 + 2O2 → CO2 + 2H2O
The given equation represents a combustion reaction, where methane (CH4) reacts with oxygen (O2) to form carbon dioxide (CO2) and water (H2O). The release of 218 kcal indicates that this reaction is exothermic, releasing heat energy.
The balanced chemical equation for the reaction between CH4 and O2 is as follows: CH4 + 2O2 -> CO2 + 2H2O By comparing the moles of CH4 and O2 given, you can see that O2 is the limiting reactant because it will be completely consumed before all of the CH4 can react.
The balanced chemical equation for the reaction is: CH4 + 2O2 -> CO2 + 2H2O Using the molar masses of CH4 and O2, we can calculate the moles present in 24g of CH4 and 96g of O2. From there, we can determine the limiting reactant and the amount of product formed.