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What type of shape will always have its centroid within the of the lamina?
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How would you find the center of any shape?
Sketch the shape onto a uniform lamina and cut it out accurately.Suspend the lamina from any point on its perimeter and mark the vertical from the point of suspension. Repeat from another point on the perimeter. The two vertical lines should meet at the centroid. In order to confirm your result, repeat another time.As a final test, balance the lamina from the point so found. It should remain horizontal.
What are medians and what is the point called where they meet?
The median of a triangle is a straight line from a vertex to the midpoint of the opposite side. The three medians of a triangle meet at the centroid. If the triangle is made of uniform material the centroid is the centre of mass of the triangular shape.
Can calculate the centre of gravity of irregular shape by aid any software?
With autocad software 1.Draw any shape 2.Covert to poly line 3.Type region in command bar 4.Type massprop in command bar 5.Note down values of centroid(x,y) by pressing F2 6.Type line command 7.Input centroid values(X,y) in command bar 8.centroid of the particular shape can be located. Tyr it BEST OF LUCK
How do you do area for an irregular shape?
There are three main methods: Method 1: The simplest situation is one in which the irregular shape can be divided up into shapes whose areas can be calculated. For example, the outline of an ice-cream cone may be viewed as a triangle with a semi-circle on top. So calculate the areas for the bits and add them up. Method 2: Trace the shape onto dense lamina of uniform thickness. Cut out the shape and measure its mass. Next cut out a UNIT square of the same lamina and measure its mass. Then Area of irregular shape = Mass of irregular lamina/Mass of lamina square. Method 3: Trace the shape onto a sheet of paper with square gridlines on it. Count the number of whole (or almost whole) squares inside the shape = A. Count the number of squares where approximately half is inside the area = B. Ignore all squares where only a tiny bit is in the marked area. Then, Area of irregular shape = (A+B/2)*area of unit square in the grid. The finer the grid, the more accurate your result, but also the harder you'll have to work.
How do you find the area of a irregular quadrilateral without breaking it apart?
I do not believe that it can be done. You can get an estimate using either of the following methods:Uniform Lamina: Copy the shape onto a sheet (lamina) of material with uniform density. Cut the shape out carefully and measure its mass (or weight). Do the same for a unit square of the lamina. Then, because the lamina is of uniform density, the ratio of the two areas is the same as the ratio of the two masses. That is: Area of Shape/Area of Unit Square = Mass of Shape/Mass of Unit Square. Rearranging, and noting that the area of the Unit Square is, by definition, = 1 sq unit Area of Shape = Mass of Shape/Mass of Unit Square. Grid Method: Copy the shape onto a grid, where each grid square has an area of G square units. Count the number of squares that are fully or mostly inside the shape. Call this number W (for whole). Count the number of squares that are approximately half inside the shape and call this number H (for half). Ignore any square that are less than half in the shape. Then a reasonable estimate of the area of the shape is G*[W + H/2] square units. There is some arbitrariness about “mostly inside†and “approximately half†but there is no way around that. You will get more accurate results with finer grids, but they will also require much more effort in terms of counting the grid squares.
What type of shape will always have its centroid within the area of the lamina?
A circle will always have its centroid withing its area.
Does the centroid of a lamina coincides with the intersection of the diagonals of a rectangle?
Only if the lamina is the same shape as the rectangle!
What is the center of gravity for a lamina?
If the lamina is in two dimensions (i.e. not curled round into a third dimension) then the centre of gravity will be somewhere within the flat shape. The position of the centre of gravity will depend on the distribution of mass across the lamina. If the lamina is curled round into a third dimension then the centre of gravity will be somewhere within the volume enclosed, fully or partially, by the lamina; this may or may not be on the lamina.
How would you find the center of any shape?
Sketch the shape onto a uniform lamina and cut it out accurately.Suspend the lamina from any point on its perimeter and mark the vertical from the point of suspension. Repeat from another point on the perimeter. The two vertical lines should meet at the centroid. In order to confirm your result, repeat another time.As a final test, balance the lamina from the point so found. It should remain horizontal.
What would happen if Lamina fall into disarray?
change in shape
What could happen if the nuclear lamina fall into disarray?
change the shape of nucleus
The shape of the nucleus is maintained by?
The shape of the nucleus is maintained by the Nuclear Lamina, a net like array of protein filaments.
What are medians and what is the point called where they meet?
The median of a triangle is a straight line from a vertex to the midpoint of the opposite side. The three medians of a triangle meet at the centroid. If the triangle is made of uniform material the centroid is the centre of mass of the triangular shape.
Can calculate the centre of gravity of irregular shape by aid any software?
With autocad software 1.Draw any shape 2.Covert to poly line 3.Type region in command bar 4.Type massprop in command bar 5.Note down values of centroid(x,y) by pressing F2 6.Type line command 7.Input centroid values(X,y) in command bar 8.centroid of the particular shape can be located. Tyr it BEST OF LUCK
How do I calculate square feet?
Square feet is a measure of area in the obsolete Imperial measurement system. There are simple formulae for shapes such as circles, ellipses, triangles, parallelograms (including special cases), trapezia and regular polygons with 5 or mire sides. The simplicity of the formula depends on what information you have about the shape. Then there are less simple formulae for more complex shapes.For totally irregular shapes the options are the grid method and the lamina method. The first involves copying the shape onto a grid and then estimating the area by counting the number of cells of the grid inside the outline. The lamina method requires making a replica of the shape onto a lamina of uniform density and then deriving its area by comparing the mass of the lamina with that of a 1 foot square (or related size) of the lamina.
What did Archimedes discover about the centroid of a triangle?
Archimedes showed that the point where the medians are concurrent is the center of gravity of a triangular shape of uniform thickness and density.
How do you find out the area of a composite figure?
There are different formulae for different shapes. Try to break down the composite firgure into components that you can add together (or subtract one from the other). An annulus, for example, is a big circle minus a smaller circle. Areas of squares, triangles, trapeziums, circles, semicircles and the process described anove will answer most high school questions. For more complex figures you may need to look elsewhere. Copy the shape onto a lamina of uniform density. Cut out the shape and find its mass. Also find the mass of a unit square of the lamina. Then area of composite shape = size of unit shape*mass of composite shaped lamina/mass of unit shape.
