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If you mean: 8x = 120 then the value of x is 15
If that's 8x = 120, x = 15
the empty set.
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.
If you mean: 8x = 120 then the value of x is 15
Without an equality sign and not knowing the plus or minus values of the given terms it follows that no solution is possible.
'x' must be zero, so the solution set is [ 0 ].
If that's 8x = 120, x = 15
the empty set.
4(2x-3)+7=8x8x-12+7=8x-8x..........-8x-12+7=0+12.....+127=12-7...-7No Solution:0≠54(2x-3+7)=8x8x-12+28=8x-8x............8x-12+28=0+12.......+1228=12-28...-28No Solution: 0≠-16
15x -1 you first look for like terms and then combine them! (8x-4x+23x) = 15x then -1 = -1 giving you the answer!
You said that 42x - 3 + 7 = 8x + 5 .Combine the like terms on the left side (the -3 and the +7):42x + 4 = 8x + 5Subtract 4 from each side:42x = 8x + 1Subtract 8x from each side:34x = 1Divide each side by 34:x = 1/34The solution set is: {34}
9x + 2 = x - 5Subtract 'x' from each side of the equation:8x + 2 = -5Subtract 2 from each side:8x = -7Divide each side by 8 :x = -7/8The solution set is { -7/8 } .
Not sure about the set builder notation, but Q = {0}, the set consisting only of the number 0.
You add 8x to each side. This gives you 5 = 16. Since this has no solution, the original equation doesn't have any solution, either.
No. That is because 2 - 8x is an algebraic expression, not an equation. And since it is not an equation, it does not have a solution.