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155.0 mL x 0.274 M SO42- reacts with 155.0 x 0.274 * 2 (Ag+/SO42-) = 84.94 mmol Ag+

84.94 mmol Ag+ is in 84.94 (mmolAg+) / 0.305 (M Ag+) = 84.94/0.305 = 278.5 mL of 0.305 M Ag+.

Na+ and NO3- are tribuned out of this reaction.

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Q: What volume of 0305 M AgNO3 is required to react exactly with 155.0ml of 0274 M Na2SO4 solution?
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