Water's accepted density is 1.00 g/mL at standard temperature and pressure so depending on temperature the 1057 grams of water will occupy just about 1057 mL.
lead and water will occupy the same volume. however the Density of lead is 207.2 g/L (grams per liter) and the Density of H2O is only 18.02 g/L so if you had the same volume of lead and water the lead would be heavier. But if you had the same Weight of both water and lead the water would have a larger volume.
The volume of 1 ml. of water equals 1 cm3.
The volume of ammonia is 19,5 L.
4 g of helium occupy 22.414 liters. So, 84.6 g of helium occupy 474.056 liters.
35.2 g * 1 g/ml = 35.2 ml
lead and water will occupy the same volume. however the Density of lead is 207.2 g/L (grams per liter) and the Density of H2O is only 18.02 g/L so if you had the same volume of lead and water the lead would be heavier. But if you had the same Weight of both water and lead the water would have a larger volume.
The volume of 1 ml. of water equals 1 cm3.
The 1000 grammes of ethanol will occupy a greater volume because its specific gravity is lower than that of water. s.g. water = ~1.0 s.g. ethanol = ~ 0.794
The volume of ammonia is 19,5 L.
The volume is 102 mL.
4 g (1 mole) of helium will occupy 22.414 liters. So, 15 g will occupy 84.05 liters
4 g of helium occupy 22.414 liters. So, 84.6 g of helium occupy 474.056 liters.
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
6.28cm^3
35.2 g * 1 g/ml = 35.2 ml
It is not possible to answer the question since that depends on the density of the item. Consider 22 g of water and 22 g of lead. The lead will occupy much less volume because it has a much greater density.
CO2(g)