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it will only be four times the height.simply use kinematics to find the relationship between height,initial speed and angle of projection theta, ull get( u^2 sin^2theta)/2g, g of course being the acceleration due to gravity, wheras range will turn out to be (u^2 sin2(theta))/g..thump in the values..very easy to see that range is 4 times the height..cheers

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Q: What will be the range if theta45 degrees and height is given in projectile motion?
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