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What will be the scale of man in an elevator moving at an acceleration of 2 ms2 if the resting scale on him is 400 newtons?
Wiki User
∙ 14y ago
answer please The forces on the man are gravity (his rest weight of 400 N) pulling down and the force of the scale , say P, pushing up on his feet. Then apply Newton's 2nd law to the man; mass x acceleration = net force on man: (mass = 400/9.8 = 40.8 kg) ma = P -400 P = ma + 400 Now P is the force the scale exerts on the man. From Newton's third law the man will exert an equal force on the scale. This force is therefore the scale reading and the man's apparent weight. If the acceleration is up then a = 2 m/ss , and P = (40.8)(2) + 400 = 481.6 N If the acceleration is down then a = -2 m/ss, and P = -(40.8)(2) + 400 = 318.4 N
Wiki User
∙ 14y ago
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