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Assumptions:

Density of water = 1000 kgm-3.

Gravitational acceleration = 9.81 ms-2

To calculate the pressure head of a 1 m depth of water, it is necessary to find the unit weight:

Unit Weight = Density x gravity

Unit Weight = 9810 Nm-3

To calculate the pressure head at the base of the column of water:

Pressure = Unit Weight x Depth

Pressure = 9810 x 1

Pressure = 9810 Pa

The resulting pressure is 9.81 kPa.

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Q: What will the pressure be at the base of a 1 meter high column of water?
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