This is a voltage drop question. The answer is for two voltages as none was stated.
A #6 copper conductor will limit the voltage drop to 3% or less when supplying 12.5 amps for 300 feet on a 120 volt system.
A #12 copper conductor will limit the voltage drop to 3% or less when supplying 6.25 amps for 300 feet on a 240 volt system.
As you can see at 120 volts, a wire sized two sizes up will be needed. At 240 volts you can downsize one size. If it is possible to find a replacement heating element that will fit the smoker with a 240 volt rating that would be the way to go. Another method would be a transformer fed with 240 volts and have it located at the smoker end of the circuit. The minimum size of the transformer would be 1500 VA (1.5 kW). A comfortable range would be 2000 VA or 2.0 kW step down transformer.
A #10 copper wire with an insulation factor of 60, 75 and 90 degrees C is rated at 30 amps. As to how many amps the wire can carry, the conductor is allowed to be loaded up to 80%, so 30 x .8 = 24 continuous amps.
A #6 copper conductor with an insulation factor of 75 or 90 degrees C is rated at 65 amps.
15 amps.
Awg #6
Overheating of electrical wiring is overcome by installing the correct size conductors to carry the load amperage of the equipment. Use a larger size wire to the load. The main purpose of the breaker is to protect the wire that is connected to it. If the wire becomes overloaded due to a high current flow the breaker will trip.
Normally wire is sized by the amperage of the load. In this case the wire size is calculated by knowing the length of the run to the load and the amperage of the device to be connected. By knowing the length, the wire size has to be increased to allow for voltage drop over the distance from the supply to the load.
The frequency has no direct relationship to the size of wire. Wire is sized as to the amount of current a load draws in a circuit.
A #6 copper wire with an insulation factor of 75 or 90 degree C is rated at 65 amps.
AWG # 8
Awg #6
Depends on the load it will carry which you failed to list.
Yes, a #10 wire will carry 30 amps for 30 feet. If the load is rated as continuous then the wire will have to be derated to 80% capacity which will leave you with 24 workable amps. If the load demands currents higher that 24 amps then you will have to go to the next wire size up which is a #8 which is rated at 45 amps.
Depends on the load it will carry which you failed to list.
The wire size is large enough to carry the load current and that the cord is properly voltage rated.
AWG # 6 copper
a fuseable link is just a length of wire that will carry a certain load. check the awg (american wire guage) ratings and install that size wire at the power source of that circuit
The amperage flowing through a wire is directly related to the load placed on the circuit, and has nothing to do with wire size, except that a larger wire will carry more amperage. Increasing wire size will not lower amperage but will allow the circuit to carry more amperage if the breaker is also increased in size. No. Ohm's law tells us that V = IR. For a given load, R is constant, and thus the only way to reduce current is to increase voltage.
Overheating of electrical wiring is overcome by installing the correct size conductors to carry the load amperage of the equipment. Use a larger size wire to the load. The main purpose of the breaker is to protect the wire that is connected to it. If the wire becomes overloaded due to a high current flow the breaker will trip.
Normally wire is sized by the amperage of the load. In this case the wire size is calculated by knowing the length of the run to the load and the amperage of the device to be connected. By knowing the length, the wire size has to be increased to allow for voltage drop over the distance from the supply to the load.
Wire size is based on the amperage of the load. Without knowing what the motors's full load amperage is, an answer can not be given.