Distance * Force / Calories
The simplistic solution is as follows: The component of the force in the horizontal plane is 41.8*cos(25) = 37.9 N. The distance travelled is pi*18 metres so work done = 37.9*18 = 2142 Joules.
-10
Depends... they are doing the same amount of work on the wagon/child. HOwever, if you take everything into account... say the diffrent masses of the father and mother, then the bigger of the two would be doing more work.
Wagon has two syllables.
There are two syllables in the word wagon. The syllables are wag-on.
Hhhh
force
force
A child in a wagon seems to fall backward when you give the wagon a sharp pull forward because the force that is exerted on te wagon is greater than the force of the friction pushing the child forward while the wagon is accelerating forward. If the force was great enough or if the wagon were to continue being pushed with a constant or increasing force, the child would eventually fall off the wagon. If the wagon's surface had no friction and there was no wind blowing against the wagon but there was friction on the ground the wagon is rolling on, then the child would stay in the same position and would fall of the wagon if the wagon were to travel far enough. If the surface of the wagon had no friction, there was no other force stopping the wagon, then the child wouldn't move his position while the wagon wouldn't stop ever making it so the child had to eventually fall assuming the wagon is finite and doesn't go all the way around in a circle around a center of gravity.
Calculate the distance first. Then multiply distance x force.
Friction is necessary to cause the wheels to rotate about the axis of the wagon-- without it the wagon would just slide over the surface.
Work = (force) x (distance)Work = (33N) x (13m) = 429 N-m = 429 joulesIF the force is in exactly the same direction as the motion of the wagon.
You reset a circuit breaker by pushing the reset button.
False. Since Force=mass*acceleration, decreasing mass will increase acceleration for the same applied force.
If a wagon is moving at a constant velocity, the total applied force must equal the frictional forces that resist the continued motion of the wagon. If they were not equal, the wagon would accelerate. In positive acceleration, it would speed up, and in negative acceleration, it would slow down. Think it through and you'll see that this is the only answer that makes sense. And not only does it make sense, it is true. The laws of physics are in force here.
Of course not. But decreasing the mass of the wagon mayincrease the effectiveness of the force used to pull it.Look at it this way:Whether I'm trying to pull a truck or a little red wagon, makes no differencein the maximum amount of force I'm able to apply. But my maximum can movethe little red wagon a lot faster and a lot farther than it can move the truck.
9.19 m/s^2