You can't tell the linear dimensions from just knowing the area. There are an infinite number
of rectangles, all with different dimensions and perimeters, that all have an area of 64 acres.
Here are a few examples. Each of these rectangles encloses 64 acres:
Length x Width . . . Perimeter (distance around)
1670-ft x 1669.4-ft, 6678.7-ft, 1.265 miles
1920-ft x 1452-ft, 6744-ft, 1.277 miles
1936-ft x 1440-ft, 6752-ft, 1.279 miles
2178-ft x 1280-ft, 6916-ft, 1.310 miles
2560-ft x 1089-ft, 7298-ft, 1.382 miles
2880-ft x 968-ft, 7696-ft, 1.458 miles
3872-ft x 720-ft, 9184-ft, 1.739 miles
17424-ft x 160-ft, 35168-ft, 6.661 miles
The distance around the earth at forty degrees South Latitude would be 19,049 miles. The circumference of Earth at the equator is 24,902 miles.
For example, a square of 1000 miles on side would have such an area. Or a rectangle that is a million miles long, and 1 miles wide, etc.
AnswerMiles, and that distance is about 480.8 miles
The distance to cover is around 900 Nautical Miles. A jet airplane would take about 2.5 hours to fly this.
Miles or kilometers would do.
The distance is around 650 km which would be around 404 miles.
The distance would be around 200 kms.
The distance would be around 30 miles.
miles
The distance in miles is about 1290 miles and would take you around 21 hours to drive.
"Perimeter" means the distance around something. Just add the four sides of the rectangle.
If you imagine a rectangle 20 miles wide and 40 miles long, the area of that rectangle would be 800 square miles.
Around 500 miles would be common.
The distance from Walsall to London (as the crow flies) is around 110 miles. The distance to drive from Walsall to London on the shortest possible route is 124 miles. This would take about two and a half hours. The distance from Walsall to London (as the crow flies) is around 110 miles. The distance to drive from Walsall to London on the shortest possible route is 124 miles. This would take about two and a half hours.
Seven 9 inch squares placed end to end would form a rectangle that was still 9 inches wide but 7 x 9 = 63 inches long. The distance around such a rectangle would measure its perimeter. Two sides are 9 inches long and two sides are 63 inches long. The perimeter would be 63 + 63 + 9 + 9 = 144 inches.
If it's a big town, then miles.
There is no definitive answer for this question. There are actually an infinite number of valid answers, depending completely on the proportions of the 20-acre rectangle.The shortest possible distance around a 20-acre rectangle is 3,733.52 feet; in this case the rectangle is actually a square that is 933.38 feet on a side. Every other possible rectangle would have a longer circumference.ExamplesA rectangle that measures 500 feet by 1,742.4 feet would enclose 20 acres; it would have a circumference of 4,484.8 feet.A rectangle that measures 200 feet by 4,356 feet would enclose 20 acres; it would have a circumference of 9,112 feet.A rectangle that measures 50 feet by 17,424 feet would enclose 20 acres; it would have a circumference of 34,948 feet.As these examples illustrate, the distance around the 20-acre rectangle increases dramatically as the rectangle becomes farther from square. In fact, the upper limit of the circumference would be defined as "approaches infinity" as the short sides of the rectangle approach zero in length.