That would depend on how many cards you drew and whether you re-inserted the cards drew back into the deck before re-drawing. I'll list a few examples.
Say you drew:
- 4 cards without re-inserting the cards you drew earlier back into the deck
The probability of drawing 4 hearts would thus be: 13/52 * 12/51 * 11/50 * 10/49 = 0.00264 or 0.264%.
- 4 cards but this time you re-insert the cards you drew earlier back into the deck
The probability of drawing 4 hearts would thus be: 13/52 * 13/52 * 13/52 * 13/52 = (13/52)^4 = 0.00391 or 0.391%
Presuming a standard 52 card deck, the chance of drawing the 6 of hearts (or any specific card for that matter) is 1/52.
Considering there is 52 cards in a deck and 4 queens.... That would be the probability of 4 out of 52... 4/52 = 1/13 ~0,077
The probability of drawing one ace from a deck of 52 cards is 13 to 1 as there are 4 aces in a deck of 52 cards. The probability of then taking another ace is then 17 to 1 as there are now 3 aces in a deck of 51 cards. The total probability for the two events in succession would now be: (13 x 17) to (1 x 1) which is 221 to 1.
If we're talking cards of all suits 2-10 then there are 36 number cards. That would then be 36/52 which would be 69.2 percent of the time.
The question is a little ambiguous. The simpler version is: if you picked up a shuffled deck of cards and drew two cards from it, what is the possibility that they would both be fives? The probability of drawing the first five is 4 out of 52, or 1/13. The probability of drawing the second five is then 3 out of 51, or 1/17. Combining these, you get that this should happen on average once in 13x17 = 221 tries. The more complicated version is: what is the probability that if you KEEP drawing cards from the deck that you will EVENTUALLY pull out two fives in a row? This is somewhat more likely, but the math does get complicated.
Presuming a standard 52 card deck, the chance of drawing the 6 of hearts (or any specific card for that matter) is 1/52.
There are a total of 4 kings, and a total of 13 hearts; from that, you must subtract 1, since otherwise you would count the king of hearts double. Thus, in a pack of 52 cards, your probability is (4 + 13 - 1) / 52, or 16/52.
You need to state a problem. If for example you ask what is the probability of drawing a heart or diamond in a single draw from a standard deck of 52 cards the answer would be .5
Considering there is 52 cards in a deck and 4 queens.... That would be the probability of 4 out of 52... 4/52 = 1/13 ~0,077
The probability of drawing a king is 4:52The probability of drawing a diamond is 13:52 (or 1:4)The probability of drawing a king (0.07692...) then replacing that king into the deck then drawing a diamond is 0.019230769.If you leave the king out, the probability will be slightly greater (4/52) * (13/51)Unless the king you left out of the deck was a king of diamonds, in which case, the probability would be (4/52) * (12/51)
Here number of sample points that is total possible outcomes would be 52C3.Event A = Three cards draw are hearts.So here we can select 3 hearts out of 13 hearts in 13C3 ways...Therefore the required probability would be=(13C3)/(52C3)=286/22100=0.01294Kunal K.
since there is only one Ace of Spades and 52 cards in a deck the probability would be 1/52.
The probability of pick a red ace out of a standard deck of cards would be 1/26 because there are two read aces, the ace of diamonds and the ace of hearts.
The probability of drawing one ace from a deck of 52 cards is 13 to 1 as there are 4 aces in a deck of 52 cards. The probability of then taking another ace is then 17 to 1 as there are now 3 aces in a deck of 51 cards. The total probability for the two events in succession would now be: (13 x 17) to (1 x 1) which is 221 to 1.
If we're talking cards of all suits 2-10 then there are 36 number cards. That would then be 36/52 which would be 69.2 percent of the time.
Probability is 1/2 or 50%. Explanation: A normal deck of cards has 52 cards, consisting of four different suits each having 13 cards. Two suits are red, and two are black. This means the deck has 26 red cards. The probability that a red card will be drawn out of the 52 cards is 26 / 52 = 1/2.
The question is a little ambiguous. The simpler version is: if you picked up a shuffled deck of cards and drew two cards from it, what is the possibility that they would both be fives? The probability of drawing the first five is 4 out of 52, or 1/13. The probability of drawing the second five is then 3 out of 51, or 1/17. Combining these, you get that this should happen on average once in 13x17 = 221 tries. The more complicated version is: what is the probability that if you KEEP drawing cards from the deck that you will EVENTUALLY pull out two fives in a row? This is somewhat more likely, but the math does get complicated.