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What is the probablity of getting a reading between 1.00 and 1.75?
That would depend quite heavily on what it is that you're reading.
What is the probablity of drawing a diamond then a red card?
The probablity is .245098. The way you would solve this is (13 C 1)*(25 C 1) / (52 C 2).
What would a probablity of 40 percent be?
The same as odds of 3 to 2 against it.
What is the experimental probability of rolling a 5 on a standard die if you had trials and 15 successes?
On an unweighted die, regardless of how many successes you've had, your chance of rolling a five will be one in six. The chance of you rolling a die 16 times and getting a five each time would be 1/616, or 0.00000000000035447042. The chance of rolling a die 16 times and getting the same number (regardless of what that number is) each time, would be 1/615, or 0.00000000000212682249 Regardless of how slim that chance is though, your chance on the next roll will still be 1/6. However, if this is meant as a "real world" question, then your chances of rolling the same number so many times in a row is so low that at that point, your odds would be much higher of there being something odd with the die, or with your experiment. At that point, it would be sensible to say that the odds are very good of rolling another 5, regardless of the math, as there seems to be another factor affecting your outcome.
Would you expect the probability for the simple event rolling a 6 to be greater than or less than the probability of the compound event rolling a 6 and getting heads on a coin?
The probability of rolling a 6 on a fair six-sided die is ( \frac{1}{6} ). For the compound event of rolling a 6 and getting heads on a coin, the probability is ( \frac{1}{6} \times \frac{1}{2} = \frac{1}{12} ). Since ( \frac{1}{6} ) is greater than ( \frac{1}{12} ), we would expect the probability of rolling a 6 to be greater than the probability of the compound event.
What are the odds of rolling less that a 4 when rolling a die once?
if you rollid a die once the odds of getting less than four would be 3/6 or 50%.
What would be the theoretical probability of rolling a die 50 times and rolling a 2?
The probability of rolling at least one 2 in fifty rolls of a standard die is 1 - (5/6) 50, or about 0.99989012. This calculation starts by looking at the probability of not rolling a 2, which is 5/6. To repeat that 50 times in a row, you simply raise that to the 50th power, getting 0.000109885. Then you subtract the result from 1 to get the probability of not succeeding in not rolling a 2 in fifty tries. Expressed in normal "odds" notation, this is about (100000 - 11) in 100000, or about 99989 in 100000.
What is the theoretical probability of rolling a 5 on a number cube if it is rolled 300 times?
The theoretical probability of rolling a 5 on a standard six sided die is one in six. It does not matter how many times you roll it, however, if you roll it 300 times, the theoretical probability is that you would roll a 5 fifty times.
What are the chances of rolling doubles 7 times in a row?
The probability of rolling doubles on a fair six-sided die is 1/6. To roll doubles 7 times in a row, you would need to multiply this probability by itself 7 times, resulting in (1/6)^7. This equals approximately 1 in 78,364,164,096, which means the chances of rolling doubles 7 times in a row are extremely low.
What would happen if there was no friction when a tire was rolling on the ground?
It would keep rolling.
What is the probability of rolling a 5 or getting tails?
Your question is very vague but if we assume "rolling a 5" is rolling a five on a six sided dice then the probability of that would be 1/6 since there are 6 sides and 5 is just 1 side. Again your question is very vague but if we assume "getting tails" means getting heads or tails on a 2 sided coin then the probability of that would be 1/2 since there are 2 sides and tails is just 1 side.
Would walking impossible without rolling friction?
Yes it would, thank God for rolling friction
