... go on?
"What would be the side length of a square with an area of 50 cm2?"
side A x side B = area
for a square side A = side B so
(side A)2 = area
or sqrt(area) = side A
Wiki User
∙ 13y agoMultiply width by length to get the area. The answer would be 1450 square feet.
Area = 10*5 = 50 square feet
yes they can the square could have a side of sqrt of 50 inches just multiply that by itself and you have 50sq inches the rectangles could have a length of 5 and a length of 10. multiply them to gether and y ou have 50sq in
Its area is virtually indistinguishable from 50 square feet.
It depends on the shape of the area. If the area is square, each side would be 10 feet long. If the area is a rectangle, the length of a long side multiplied by the length of a short side would be 100, e.g., 50 feet by 2 feet, or 25 feet by 4 feet. If the area is an odd shape, like a polygon, a star, a crescent, or an oval, the sides could be almost any lengths.
The square root of 50 would make a perfect square. Something around 7.something for each side of the square. That's the biggest area you could have. The smallest? two sides of 24.99999 and two sides of 0.00001
P = 200 => length of side = 200/4 = 50 metresThen area = 50*50 = 2500 sq metres.
Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length). so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units. As a square has sides of equal length the square on one side is actually the area of the square. i.e. the area of a square with a diagonal of 10 units is 50 square units. or generically the area of a square with a diagonal of length 'x' = (x2)/2
If diagonal is 10 then each side is sqrt 50 (Pythagoras) and area is sqrt 50 x sqrt 50 ie 50
43,560 square feet = 1 acreA square that measures 50 feet on every side has an area of (50 x 50) = 2,500 square ft.2,500 square feet = (2,500 / 43,560) = 0.0574 of an acre (rounded)
7.071 centimetres (to two decimal places).
Multiply width by length to get the area. The answer would be 1450 square feet.
1 side = 50 / 4 = 12.5 inches, so area = 12.5 * 12.5 = 156.25 sq. inches
Area = 10*5 = 50 square feet
Its area is virtually indistinguishable from 50 square feet.
yes they can the square could have a side of sqrt of 50 inches just multiply that by itself and you have 50sq inches the rectangles could have a length of 5 and a length of 10. multiply them to gether and y ou have 50sq in
It depends on the shape of the area. If the area is square, each side would be 10 feet long. If the area is a rectangle, the length of a long side multiplied by the length of a short side would be 100, e.g., 50 feet by 2 feet, or 25 feet by 4 feet. If the area is an odd shape, like a polygon, a star, a crescent, or an oval, the sides could be almost any lengths.