1 side = 50 / 4 = 12.5 inches, so area = 12.5 * 12.5 = 156.25 sq. inches
Chat with our AI personalities
(20,5)
Use as much of the string as is possible to make the circle. In the limit, the circumference of the circle is 50 inches and the perimeter of the square is 0. This gives a circle with an area of 198.94 sq inches and a square with an area of 0 sq inches. Any string moved from the circle to the square will reduce the total area.
Diameter = 50 inches Radius = 25 inches Area of circle = pi x 25 x 25 = 3.1415 x 625 = 1963.44 square inches which is equivalent to 1963.44/144 = 13.63 square feet
The rectangle with the smallest perimeter for a given area is the square. The rectangle with the greatestperimeter for a given area can't be specified. The longer and skinnier you make the rectangle, the greater its perimeter will become. No matter how great a perimeter you use to enclose 24 ft2, I can always specify a longer perimeter. Let me point you in that direction with a few examples: 6 ft x 4 ft = 24 ft2, perimeter = 20 ft 8 ft x 3 ft = 24 ft2, perimeter = 22 ft 12 ft x 2 ft = 24 ft2, perimeter = 28 ft 24 ft x 1 ft = 24 ft2, perimeter = 50 ft 48 ft x 6 inches = 24 ft2, perimeter = 97 ft 96 ft x 3 inches = 24 ft2, perimeter = 192.5 ft 288 ft x 1 inch = 24 ft2, perimeter = 576ft 2inches No matter how great a perimeter you find to enclose 24 ft2, I can always specify a rectangle with the same area and a longer perimeter.
you don't. that's like asking how many dollars are in 10 feet. the units "linear feet" and "square feet" represent two totally different types of quantities. if you have a rectangle made up of 216 linear feet, the area (in square feet) could be practically anything. If the sides are 50 and 58, the perimeter is 216 linear feet and the area is 2,900 square feet. But if the sides are 10 and 98 feet, the perimeter is still 216 linear feet, while the area is now 980 square feet.