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x+5 = 7 - (2x) 3x = 2 x = 2/3 The number is 2/3
Expressed algebraically, this is equal to x - 92.
n - 13 = 7
The result is the knowledge of another number that is equal to that percent of the original number,
It is: 10+(-1) = 9
Its 11
18
If ten times the number n decreased by 13 is equal to the square of the same number n increased by 3, then the value of n is either 8 or 2.
x+5 = 7 - (2x) 3x = 2 x = 2/3 The number is 2/3
x - 2 = 7 + x/4 4x - 8 = 28 + x 3x = 36 x = 12
seventy five descreasedby five
Expressed algebraically, this is equal to x - 92.
How do you write half a number decreased by 8 is equal to the sum of the number and 14
If AD increased, all else being equal, the price level would increase.
n - 13 = 7
c is less than or equal to 29
x-4=8+x/5 5(x-4)=5(8+x/5) 5x-20=8+x 4x=28 x=7