At least two heads with two coins? You can't get more.
There are 4 different outcomes:
tail-tail, head-tail, tail-head and head-head.
You can use one out of four - which gives us the probability 1/4 = 0.25 = 25%
The probability is 50-50.
1/2 or 50% (1/8 prob of 0H + 3/8 prob of 1H)
The probability is 3/4.
50%
50%
3/8
The probability is 50-50.
The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.
It is the event that one of the two coins lands showing tails and the other shows heads.
1/2 or 50% (1/8 prob of 0H + 3/8 prob of 1H)
(0.5)n
The probability is 3/4.
It is 1/2^7 = 1/128.
Prob(at least 4 heads) = Prob(4 heads) + Prob(5 heads) = 5/32 + 1/32 = 6/32 = 3/16
Yes, quite easily.
Its not laying anything. It's getting tossed.
It is 0.25