When 2 dice are rolled, the probability of getting a sum less than 4 or greater than 9 is 2 in 9.
There are 36 permutations of two six sided dice, 1-1, 1-2, ..., 1-6, 2-1, ... 2-6, ..., 6-1, 6-2, ... 6-6. Of these permutations, 3 have a sum less than four, 1-1, 1-2, and 2-1, and 5 have a sum greater than nine, 4-6, 5-5, 5-6, 6-4, 6-5, and 6-6. Add these probabilities together and you get (3 + 5) in 36, or 8 in 36, or 2 in 9.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
Two standard dice cannot have a sum greater than 12. The probability, then, of getting a sum greater than 15 is zero.
If they are normal dice, the probability is 0.
It is 15/36 = 5/12
It is 5 over 6.
Assuming these are regular dice, the probability is 1.
The probability of rolling 12 with 2 dice is 1 in 36. The probability of not rolling 12 with 2 dice is 35 in 36.
The probability is 35/36.
The probability is 1, if the dice are rolled often enough.
Probably.
The probability is 8/36 or 2/9
It is 1/6.
1/12 or .083