Let us use the letter G for the number of girl in the class and B for the number of boy.
The total number of students is B+G. We are told the original percent of girls went from 40 to 50 %.
So when there was 40% girls, we had G/(B+G) =.4 Now we add 5 new girls and the percent of girls is .5
So
(G+5)/(B+G+5)=.5
Let's cross multiply the first equation and we have
.4G+.4B= G or
.4B=.6G
B=(3/2)G
The second equation becomes (G+5)=(1/2)G+(1/2)B+(5/2)
This is the same as
2G+10=G+B+5
Or
G=B-5
Now plug in B=(3/2)G
G=(3/2)G-5 or
-1/2 G=-5
or
G=10 This means B was (3/2)x10=15.
So at first we had
10/25 girls or 40% then when we added 5 girls we have
15/30 girls or 50%
So in the original class we had 10 girls and 15 boys and then we had 15 girls and 15 boys.
This could be done without the equations, since the numbers are pretty easy in this case. But this method works for any numbers.
The increase is 10 out of 25. 10/25 = 0.4 = 40%
5
48
The median is the middle number in a data set. The lower class boundary is the first quartile or number that is 25 percent lowest in the data set.
60 percent are women
The class enrollment increased by 3 students. This is the equivalent of 20%.
The increase is 10 out of 25. 10/25 = 0.4 = 40%
5
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48
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There are 28.8 to equal it 29 females are in a class
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There was nothing but upper class people in the Nazi party.
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