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When The sum of the squares of two consecutive positive odd integers is 202 what are the integers?
Wiki User
∙ 14y ago
Let n be an integer, then two consecutive odd integers can be expressed as n and n+2. The equation can the be wrote as n2 + (n+2)2 = 202
= n2 +n2 + 4n +4 = 202
which implies
2n2 + 4n - 198 = 0
which implies
n2 + 2n - 99 = 0
the quadratic formula can then be used to solve for n as
n = (-2 +- (4 - 4*-99)^(1/2))/(2)
= -1 +- (1/2)*(400)^(1/2)
= - 1 +- 10
take the positive solution and you get
n = 9
which implies your two consecutive integers are 9 and 11.
Wiki User
∙ 14y ago
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The sum of the squares of two consecutive odd integers is 202 find the integers?
9 and 11 92 = 81 112 = 121 81+121 = 202
What is the largest three digit number that is the sum of the squares of two consecutive even natural numbers?
202 + 222 = 400 + 484 = 884
If a sum of a particular set of 3 consecutive positive integers is a 3mdigit palindrome and the sum is less than 220 what is the greatest possible value for the largest of the 3 integers in the set?
The answer is 58. 56+57+58 = 171 171 is the largest palindrome less than 220 that can be divided by three. Further palindromes are: 181, 191, 202 and 212.
What is the longest string of consecutive composite numbers in eratosthenes?
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11
What is the median of 201 202 202 205 209?
It is 202, the middle value.
If the sum of the squares of two consecutive odd positive integers is 202 what are the integers?
112+92 is 202.
The sum of the squares of two consecutive odd integers is 202 find the integers?
9 and 11 92 = 81 112 = 121 81+121 = 202
What is the largest three digit number that is the sum of the squares of two consecutive even natural numbers?
202 + 222 = 400 + 484 = 884
If a sum of a particular set of 3 consecutive positive integers is a 3mdigit palindrome and the sum is less than 220 what is the greatest possible value for the largest of the 3 integers in the set?
The answer is 58. 56+57+58 = 171 171 is the largest palindrome less than 220 that can be divided by three. Further palindromes are: 181, 191, 202 and 212.
What are the ratings and certificates for The Hollywood Squares - 1965 1-202?
The Hollywood Squares - 1965 1-202 is rated/received certificates of: USA:TV-G
What are the release dates for The Hollywood Squares - 1965 1-202?
The Hollywood Squares - 1965 1-202 was released on: USA: 27 July 1967
What are the release dates for The Hollywood Squares - 1965 2-202?
The Hollywood Squares - 1965 2-202 was released on: USA: 11 June 1968
The sum of two consecutive is 203 what are the integers?
101 and 102 Explanation: I'll use x to represent the first integer and x + 1 to represent the second integer (consecutive integers are one right after another). x + x + 1 = 203 2 x = 202 x = 101 The two numbers are 101 and 102.
What is the sum of the first 100 positive even integers?
use this formula: S=(N/2)(F+L) S= the sum of the first 100 positive even integers N= the number of terms F= first term L=last term Since we are using the first 100 positive integers we will replace "N" with 100. so it will look like this : S=(100/2)(F+L) Next we must substitute the "F" with the first positive term which is the number 2. So now it looks like this: S=(100/2)(2+L) We use the number 2 because our positive integers are 2,4,6,8,10,12...... you get the picture. Now we must substitute the "L" with the last positive term which is 200. As you probably guessed it will look like this: S=(100/2)(2+200) We use the number 200 because it is the last positive even integer. If we used 202 then that would have meant we used the 101th positive even integer and we don't want to do that. == == We should solve the numbers inside the parenthesis first. S=(100/2)(2+200) 100 divided by 2 = 50 So: S=50(2+200) 2+200=202 That means: S=50(202) 50 x 202 = 10,100 Finally: S=10,100 There you go! Wasn't that easy? Note: This formula only works if you are looking for the sum of the first 100 positive or negative, even or odd integers. It sucks cause this formula is the Bomb right? Oh well
What is 202 times 202?
202 x 202 = 40,804
What is the longest string of consecutive composite numbers in eratosthenes?
200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210...yep all 11
What are the factors of 1010?
The positive integer factors of 1010 are: 1, 2, 5, 10, 101, 202, 505, 1010
