3 out of 9
two dice are thrown once. write all the possible outcomes. find the probability of getting: (i) a total of 12 (ii) a total of 3 (iii) a total of 8
A die normally has 6 sides numbered 1 through 6. The probability of you landing on ANY number is 1:6, or you have a 1 in 6 chance of landing a 3.
There are 36 possible outcomes. Of these the following 8 meet the requirements: (1,3), (2,2), (3,1), (1,5), (2,4), (3,3), (4,2) and (5,1). So the probability of 4 or 6 is 8/36 or 2/9
There is a one out of six chance.
The probability of the outcomes is 1.
1 out of 6
3 out of 9
the probability is 2/6 or 1/3
two dice are thrown once. write all the possible outcomes. find the probability of getting: (i) a total of 12 (ii) a total of 3 (iii) a total of 8
When a fair die is thrown the probability that a prime number will occur is 2:1
The probability is 146/1296 = 0.1127
The first dice can show any number. However the second dice has a 1 in 6 chance of being the same as the first. Hence the probability of getting two numbers the same is 1/6.
A die normally has 6 sides numbered 1 through 6. The probability of you landing on ANY number is 1:6, or you have a 1 in 6 chance of landing a 3.
If two dice (not dices!) are thrown then the probability that you get an even number on one die is 27/36 = 3/4
There are 36 possible outcomes. Of these the following 8 meet the requirements: (1,3), (2,2), (3,1), (1,5), (2,4), (3,3), (4,2) and (5,1). So the probability of 4 or 6 is 8/36 or 2/9
There is a one out of six chance.