Wiki User
∙ 9y agoThe probability is 146/1296 = 0.1127
Wiki User
∙ 9y agoThe probability of getting a number on the first dice and the same number on the second dice (e.g. a 3 and a 3) is 1/6 x 1/6 = 1/36. There are 6 ways of getting a doublet (i.e. a double 1, 2 , 3, 4, 5 or 6) so the total probability is 6 x (1/36) = 1/6.
Odd numbers are any number with 1,3,5,7,9 at the end of them i.e 135 but odds alone is used to represent chances of an event to happen against chances of not to happen, it is in relation to probability but it is not the same. For example, the probability when you throw two dices to obtain 1 and 1 is 1/36 but the odds are represented as 1 against 35, usually represented as 1 : 35.
Many games utilize dice, for instance Monopoly uses two dice to advance game pieces around the board. Alternatively, RISK uses dices rolled against one another to determine the outcome of player attacks. I'm sure there are many other examples, just brows the game board section Matel or Hasbro and I'm sure you will find other games that utilize two dice.
Possible outcomes of a single dice are 6 ( 1,2,3,4,5,6) So if 5 such dices are rolled then the number of possible outcomes are 6 mulitiplied by 6 five times. 6x6x6x6x6x6=46656 possible outcomes.
If two dice (not dices!) are thrown then the probability that you get an even number on one die is 27/36 = 3/4
1/36
Since there are only odd & even numbers, the probability is 1/2 or 0.5.
6x6x6=216
Singular: die Plural: dice Nonsense: dices! The probability is 2/36 = 1/18
The probability of rolling two 6-sided dice and getting the same number on each is 1/32, or "one out of thirty two". This is because there are 6 oppurtunities on each dice, and the probability of getting the same of the 6 oppurtunites on two dice is 6 squared, which is 32.
to get a 12 you need to roll two a six on each of the two dices. the probability of rolling a six 1/6 on each, and to get six on two, is the 1/6 *1/6 = 1/36
The probability of rolling a total of 3 or less on two dice is 3 in 36 or 1 in 12.
The probability of getting a number on the first dice and the same number on the second dice (e.g. a 3 and a 3) is 1/6 x 1/6 = 1/36. There are 6 ways of getting a doublet (i.e. a double 1, 2 , 3, 4, 5 or 6) so the total probability is 6 x (1/36) = 1/6.
The sample space is 62 or 36. Take the 1st die rolled. It must start with a 2, 4, or 6. Likewise, the 2nd die rolled must be a 2, 4, or 6. So, with the 1st die at 2, the 2nd die could be 2, 4, or 6. The same holds true for the 4 & 6. There are 9 possible rolls then that are even & even. The probability is 9/36 or 1/4.
If they are normal cubes, the probability is 1, if you roll them often enough.
1/6+1/6+1/6-1/6 =.333