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well at 156 kgls the mirrors begin to angle auxtributly. this forms a slight arc and allows image distance to become negative.
If the lens equation yields a negative image distance, then the image is a virtual image on the same side of the lens as the object. If it yields a negative focal length, then the lens is a diverging lens rather than the converging lens in the illustration.
A piece of photographic film having the negative (opposite) image of your positive print or image.
image distance is the distance from the point of incidence on the mirror, the where the image is reflected to.object distance is the distance from the actual object being reflected to the point of incidence on the mirror where it's reflected as an image.
the focal length of the eye lens is adjusted so that the image distance does not change.
the image distance will appear the same
SID stands for Source to Image Distance. This is the distance between the source of photons (anode) and the image receptor.
If the lens are thicker it affects the image distance.
The distance of the object from the mirror line should equal the distance of the image from the mirror line.
when dealing with a flat mirror object-distance and image-distance should be equal.
False, magnification is negative, which means v/u is negative as well, assuming u is always positive, it means v is negative, which means the image is virtual.add In any event, an image is not REAL - it is just an image. It may become a replica when it is recorded permanently on film etc. And of course it may be erect or inverted or reversed, or indeed a negative, but none of these are REAL.
The distance of object and the distance of image.