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decreases i believe(:

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Q: When cell size increases the surface area to volume ratio does what?
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What happens to a cell ratio of surface area to volume as the cells volume increases rapidly than its surface area?

The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.


What happens to a cell's ratio of surface area to volume as the volume increases more rapidly than its surface area?

As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.


As a cell increases in size the a. metabolic rate increases. b. surface area to volume ratio increases. c. volume increases and the surface area increases. d. surface area increases and the volume d?

As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.


What happens to a cell's ratio of surface area to volume as the cell's volume increases more rapidly than its surface area?

The ratio decreases.


What happens to a cell's ratio of surface area to volume as the cell's volume increases more rapidly than surface area?

The ratio decreases.


How does the surface area to volume ratio change as the cell size increases?

It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.


What decreases as the volume of course material increases?

The surface area-to-volume ratio.


How does a cell's ratio of surface area to volume change as the cell grows larger?

As the cell grows larger the ratio of surface area to volume increases. Larger cell = more volume for the amount surface area.


When the volume of a cube increases does the ratio of its surface area to its volume decrease?

If the length of the cube's side is 'S', then the surface area is 6S2 and the volume is S3 .The ratio of surface area to volume is 6S2/S3 = 6/S .This number is inversely proportional to 'S'. So as the side increases ...causing the volume to increase ... the ratio does decrease, yes.


What happens to a cells surface area to volume ratio as it gets smaller?

It increases.


What happens to a cell's ratio of surface area to volume as the cell's volume increases more rapidly than it surface?

it callapses


What happens to a cell's ratio of surface are to volume as its cell volume increases more rapidly than its surface area?

it decreases