decreases i believe(:
It increases.
To obtain the ratio of surface area to volume, divide the surface area by the volume.
As a cell becomes larger the surface area to volume ratio gets smaller. The volume increases by the square of the surface area. That is the main reason that one celled organisms are small.
A smaller cell has a higher surface area to volume ratio. A reason for this is volume is cubic (3D) and surface area is 2D so when surface area increases a little bit, the volume increases exponentially. And when the surface area shrinks a little bit, the volume decreases exponentially.
to obtain the ratio of surface area to volume, divide the surface area by the volume.
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.
The ratio decreases.
The ratio decreases.
It decreases. As the dimensions increase by a number, the surface area increases by the same number to the power of 2, but the volume increases by the same number to the power of 3, meaning that the volume increases faster than the surface area.
The surface area-to-volume ratio.
As the cell grows larger the ratio of surface area to volume increases. Larger cell = more volume for the amount surface area.
If the length of the cube's side is 'S', then the surface area is 6S2 and the volume is S3 .The ratio of surface area to volume is 6S2/S3 = 6/S .This number is inversely proportional to 'S'. So as the side increases ...causing the volume to increase ... the ratio does decrease, yes.
It increases.
it callapses
it decreases