When the sum of all the positive integers in the sum is exactly matched (in magnitude) by the sum of all the negative integers.
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
The sum is positive.
By adding whatever you mean with "integers of a number".
Two integers which sum to zero (e.g. 3 and -3) are additive inverses of each other. All pairs of additive inverses sum to 0 and all pairs of integers which sum to 0 are additive inverses.
Yes, it does.
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
The sum is positive.
The result of adding and integer and its opposite is negation. A + (-A) = 0 For all real integers. It has the effect of adding 0 to a sum. Example: 32 + 16 + (-16) + 5 = 37 = 32 + 0 + 5.
By adding whatever you mean with "integers of a number".
Two integers which sum to zero (e.g. 3 and -3) are additive inverses of each other. All pairs of additive inverses sum to 0 and all pairs of integers which sum to 0 are additive inverses.
Yes, it does.
No, always negative
-1, 0, 1
Zero (0).
8 and -8 8+(-8)=0 8-(-8)=16
what is the sum of the first 10 positive integers? To me, if you include 0 as the first integer, then the tenth integer is 9 and the sum is 45. If you don't include 0, the tenth integer is 10, and the sum is 55.
It would stay always stay negative if you're adding 2 negative integers.