8 and -8
8+(-8)=0
8-(-8)=16
That's because the integers may be negative. For example, the sum of (-6) and (-6) is (-12), which is less than their difference (0).
When the sum of all the positive integers in the sum is exactly matched (in magnitude) by the sum of all the negative integers.
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
No. Consider 0 and 1. Or negative numbers, whose sum produces a smaller number.
Two integers which sum to zero (e.g. 3 and -3) are additive inverses of each other. All pairs of additive inverses sum to 0 and all pairs of integers which sum to 0 are additive inverses.
8 and -8; 8 + (-8) = 8 - 8 = 0, and 8 - (-8) = 8 + 8 = 16
That's because the integers may be negative. For example, the sum of (-6) and (-6) is (-12), which is less than their difference (0).
When the sum of all the positive integers in the sum is exactly matched (in magnitude) by the sum of all the negative integers.
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
No. Consider 0 and 1. Or negative numbers, whose sum produces a smaller number.
Two integers which sum to zero (e.g. 3 and -3) are additive inverses of each other. All pairs of additive inverses sum to 0 and all pairs of integers which sum to 0 are additive inverses.
-1, 0, 1
0
Zero (0).
Let the five consecutive integers be ( x-2, x-1, x, x+1, x+2 ). The sum of these integers can be expressed as ( (x-2) + (x-1) + x + (x+1) + (x+2) = 5x ). To find the integers that sum to 0, we set ( 5x = 0 ) which gives ( x = 0 ). Thus, the five consecutive integers are -2, -1, 0, 1, and 2.
what is the sum of the first 10 positive integers? To me, if you include 0 as the first integer, then the tenth integer is 9 and the sum is 45. If you don't include 0, the tenth integer is 10, and the sum is 55.
The integers are -2, 0, 2 and 4.