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If the vectors a and b are arranged so that the head of a (the arrow bit) is at the tail of b, then c must be from the tail of a to the head of b. The vectors a and b can be swapped since vector addition is commutative.

Q: When does vector c equal a plus b?

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When b is zero.

A+c= 2a+b

a=24 b=16 c=18

(A1) The dot product of two vectors is a scalar and the cross product is a vector? ================================== (A2) The cross product of two vectors, A and B, would be [a*b*sin(alpha)]C, where a = |A|; b = |B|; c = |C|; and C is vector that is orthogonal to A and B and oriented according to the right-hand rule (see the related link). The dot product of the two vectors, A and B, would be [a*b*cos(alpha)]. For [a*b*sin(alpha)]C to equal to [a*b*cos(alpha)], we have to have a trivial solution -- alpha = 0 and either a or b be zero, so that both expressions are zeroes but equal. ================================== Of course one is the number zero( scalar), and one is the zero vector. It is a small difference but worth mentioning. That is is to say if a or b is the zero vector, then a dot b must equal zero as a scalar. And similarly the cross product of any vector and the zero vector is the zero vector. (A3) The magnitude of the dot product is equal to the magnitude of the cross product when the angle between the vectors is 45 degrees.

Because there is no way to define the divisors, the equations cannot be evaluated.

Related questions

When b is zero.

A+c= 2a+b

That depends on the value of the variables (A, B, and C). It can be anything.

a=24 b=16 c=18

If a + b + c + d + 80 + 90 = 100, then a + b + c + d = -70.

2a. (a, b and c are all equal.)

1. When the two vectors are parlell the magnitude of resultant vector R=A+B. 2. When the two vectors are having equal magnitude and they are antiparlell then R=A-A=0. For more information: thrinath_dadi@yahoo.com

(A1) The dot product of two vectors is a scalar and the cross product is a vector? ================================== (A2) The cross product of two vectors, A and B, would be [a*b*sin(alpha)]C, where a = |A|; b = |B|; c = |C|; and C is vector that is orthogonal to A and B and oriented according to the right-hand rule (see the related link). The dot product of the two vectors, A and B, would be [a*b*cos(alpha)]. For [a*b*sin(alpha)]C to equal to [a*b*cos(alpha)], we have to have a trivial solution -- alpha = 0 and either a or b be zero, so that both expressions are zeroes but equal. ================================== Of course one is the number zero( scalar), and one is the zero vector. It is a small difference but worth mentioning. That is is to say if a or b is the zero vector, then a dot b must equal zero as a scalar. And similarly the cross product of any vector and the zero vector is the zero vector. (A3) The magnitude of the dot product is equal to the magnitude of the cross product when the angle between the vectors is 45 degrees.

Because there is no way to define the divisors, the equations cannot be evaluated.

the answer is a

2s-2b= a+b+c-2b simplified that would be a+c-b.

Because it is mathematically incorrect. a^2 + b^2 = c^2 Take square root of both sides. SQRT (a^2 + b^2) = c So you see, it is not a plus b equal c.