a=24 b=16 c=18
Because there is no way to define the divisors, the equations cannot be evaluated.
z remains undefined.
2s-2b= a+b+c-2b simplified that would be a+c-b.
When b is zero.
2a. (a, b and c are all equal.)
a=24 b=16 c=18
the answer is a
Because there is no way to define the divisors, the equations cannot be evaluated.
z remains undefined.
2s-2b= a+b+c-2b simplified that would be a+c-b.
a= (+a) or a= (-) b= 2a b= 2a c= (-a) c= (+a)
Just subtract y from both sides. 'm' becomes 'A', 'b' becomes 'C' and 'B' will be equal to one.
When b is zero.
to solve ab=c+a for a:Divide both sides by b, so:a= (c+a)/b
A.
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."