Well if your question is about individual terms then the answer is no. A term in a polynomial always has coefficients listed before the variable (i.e. 3x). But if you're asking about terms within an expression, then it doesn't matter. It would be correct to write y=x-5 or y=(-5)+x.
yes
An algebraic expression for "six less than 2 times y" can be written as (2y - 6). This expression reflects that you first multiply (y) by 2 and then subtract 6 from the result.
It was the Persian mathematician Al Khwarizmi in about 820AD who first conceived the idea of algebra.
first of all you need to simplify it in the form of a+b
The evaluate a algebraic math expression you first must substitute a number for each variable. Then you must perform the operation in the correct order.
To change the phrase "14 less than the quantity k times 6" to an algebraic expression, you would first write "k times 6" as 6k. Then, you would subtract 14 from that expression to get the final algebraic expression, which is 6k - 14. This expression represents the result of taking 14 away from the product of k and 6.
Parenthesis, Exponents, Multiplication or Division(whichever come first from left to right*), Addition or Subtraction *
(n-4)/5 Remember p.e.m.d.a.s. The parentheses signify which part of the expression to do first. They are very important. You get a different answer without them.
The algebraic expression for "4 times the sum of a number and 6008" can be written as 4(x + 6008), where x represents the unknown number. This expression denotes that the number is added to 6008 first, and then the sum is multiplied by 4. To simplify, you can distribute the 4 into the parentheses to get 4x + 24032.
The algebraic expression for "8 more than half a number" can be represented as ( \frac{x}{2} + 8 ), where ( x ) represents the unknown number. This expression first calculates half of the number by dividing it by 2, then adds 8 to the result.
let x = first number let y = second number x + y =20
The algebraic expression for twice a number ( k ) plus the quantity ( s - 2 ) can be written as ( 2k + (s - 2) ). This combines the two components by first calculating twice the value of ( k ) and then adding the result to ( s - 2 ). Therefore, the complete expression is ( 2k + s - 2 ).