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Suppose p and q are two even numbers.p is even so p = 2*m for some integer m.

q is even so q = 2*n for some integer n.

Then p + q = 2m + 2n = 2*(m + n) => 2 divides p + q evenly => p + q is even.

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Q: When given two even numbers prove that when you add them together you must get another even number?
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