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When pulling out 10 cards from a standard deck of 52 what are the chances of pulling at least one ace?
Wiki User
∙ 10y ago
Prob(At least one ace in ten cards out of 52)
= 1 - Prob(No aces in ten cards out of 52)
When you start there are 48 non-ace cards out of 52,
At the next draw, there are 47 non-ace cards out of 51, and so on
= 1 - (48/52)*(47/51)* ... *(39/43) = 1 - 0.41 = 0.59
Wiki User
∙ 10y ago
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How many cards have to be drawn from a standard 52-card deck to be certain that at least 2 cards from each of the four suits will be selected?
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