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Let us give this unknown number the symbol x , then you can formulate this equation:

( x + 3 )^ 2 = 13 + ( x + 2)^ 2

x^2 + 6x + 9 = 13 + x^2 + 4x + 4

subtract x^2 from both sides, you'll obtain:

6x + 9 = 4x + 17

6x - 4x = 17 - 9

2x = 8

So, x=4

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Q: When the sum of a number plus 3 is squared it is 13 more than the number plus 2 when squared?
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