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Call the unknown number n. From the problem statement (n + 3)2 - (n + 2)2 = 11. Expanding both squares yields n2 + 6 n + 9 - (n2 + 4n + 4) = 11, or 2 n + 5 = 11, 2n = 6, n = 3.

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14y ago
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Q: When the sum of a number pluse 3 is squated it is 11 more than the sum of the number plus 2 when squared?
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