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If the length of the cube's side is 'S', then the surface area is 6S2 and the volume is S3 .

The ratio of surface area to volume is 6S2/S3 = 6/S .

This number is inversely proportional to 'S'. So as the side increases ...

causing the volume to increase ... the ratio does decrease, yes.

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Q: When the volume of a cube increases does the ratio of its surface area to its volume decrease?
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