If the length of the cube's side is 'S', then the surface area is 6S2 and the volume is S3 .
The ratio of surface area to volume is 6S2/S3 = 6/S .
This number is inversely proportional to 'S'. So as the side increases ...
causing the volume to increase ... the ratio does decrease, yes.
The cell's ratio of surface area to volume would decrease if its volume increases more rapidly than its surface area.
As volume increases surface area increase, but the higher the volume the less surface area in the ratio. For example. A cube 1mmx1mmx1mm has volume of 1mm3 surface area of 6mm2 which is a ration of 1:6 and a cube of 2mmx2mmx2mm has a volume of 8mm3 and surface area of 24mm2 which is a ratio of 1:3.
The rate at which the cell increases in size depends on the DNA. The ratio of the surface area (calculated: length x width x # of sides) is divided by the cell volume (calculated: length x width x height). THE VOLUME OF THE CELL INCREASES MORE RAPIDLY THAN THE SURFACE AREA, CAUSING THE RATIO OF SURFACE AREA OVER VOLUME TO DECREASE. This decrease causes cell malfunction. If the cell volume increases too much, then the ratio will decrease causing problems for the cell's regular functions.
The rate at which the cell increases in size depends on the DNA. The ratio of the surface area (calculated: length x width x # of sides) is divided by the cell volume (calculated: length x width x height). THE VOLUME OF THE CELL INCREASES MORE RAPIDLY THAN THE SURFACE AREA, CAUSING THE RATIO OF SURFACE AREA OVER VOLUME TO DECREASE. This decrease causes cell malfunction. If the cell volume increases too much, then the ratio will decrease causing problems for the cell's regular functions.
The cell's ratio of surface area to volume would decrease. However, this scenario is extremely unlikely.
For a cube with edge length, L. Surface area = 6L2. Volume = L3. So ratio of Surface Area / Volume = 6 / L. Therefore, as the side length, L, increases, the ratio will decrease.
As the surface to volume ratio increases the rate of in exchange increases too.
The rate at which the cell increases in size depends on the DNA. The ratio of the surface area (calculated: length x width x # of sides) is divided by the cell volume (calculated: length x width x height). THE VOLUME OF THE CELL INCREASES MORE RAPIDLY THAN THE SURFACE AREA, CAUSING THE RATIO OF SURFACE AREA OVER VOLUME TO DECREASE. This decrease causes cell malfunction. If the cell volume increases too much, then the ratio will decrease causing problems for the cell's regular functions.
The rate at which the cell increases in size depends on the DNA. The ratio of the surface area (calculated: length x width x # of sides) is divided by the cell volume (calculated: length x width x height). THE VOLUME OF THE CELL INCREASES MORE RAPIDLY THAN THE SURFACE AREA, CAUSING THE RATIO OF SURFACE AREA OVER VOLUME TO DECREASE. This decrease causes cell malfunction. If the cell volume increases too much, then the ratio will decrease causing problems for the cell's regular functions.
The surface area-to-volume ratio.
As a cell increases in size the volume increases much faster than the surface area. The possible answer is C.
The ratio decreases.