90 degrees.
Because any angle increased by k*2pi radians (= k*360 degrees) where k is an integer, is, effectively, the same angle. This implies that f(x + 2kpi) = f(x) for any angle x and any trig function f. This gives f a maximum period of 2pi radians.
Yes, torque can have a negative value in physics. Torque is vector energy. Torque is the vector analogue of Work involving force (F) and displacement (D) vectors and the angle (FD). For example Work W = -F.D= -|FD|cos(FD) and Toque T = FxD =|FD|sin(FD). Torque can be negative dependent on the sine(FD). Work and torque is an example of the quaternion nature of physics; for example Quaternion energy E = FD = -F.D + FxD, the real energy is called work F.D and the vector energy is called torque, FxD.
I believe the maximum horsepower rating was 145 at 4200 RPM ,but I don't know what the engine redline is ( 265 Ft/Lb torque at 2000 RPM )
That's power.P = FS (theta)/T; where F is force, S is distance, T is time, and theta is the angle between F and S.
Assuming the question is in the context of pie charts, the angle which corresponds to a fraction, f, of the total is makes and angle at the centre of 2*pi*f radians (= 360*f degrees).
The formula to calculate the maximum torque on a beam subjected to a specific load is T F d, where T is the torque, F is the applied force, and d is the distance from the point of force application to the point of rotation.
The net torque equation is rFsin, where represents the total rotational force (torque), r is the distance from the pivot point to the point where the force is applied, F is the magnitude of the force, and is the angle between the force and the lever arm.
The torque exerted by a force is calculated by multiplying the force by the distance from the pivot point and the sin of the angle between the force and the lever arm. In this case, the torque exerted by the force would be 8 N * 0.5 m * sin(45 degrees) = 2.83 Nm.
The torque produced by centripetal force is zero because the force is acting perpendicular to the radius of rotation. Torque is calculated as the force multiplied by the distance from the axis of rotation, and when the force and distance are perpendicular to each other, the torque becomes zero.
t = r X F, where t is torque, r is displacement, and F is force; all quantities are vectors. Because the formula contains a cross product, the magnitude of the torque is given by the expression rFsin(θ), where θ is the angle between the position vector and the force vector.
Torque is vector energy. Physicists have mistakenly defined energy as a scalar. Energy is a quaternion consisting of scalar energy (potential) and vector energy (torque). The units of torque is Joules or Newton meter, the same as work or energy..Here is the correct definition of Energy = FD = -F.D + FxD where F is force vector in Newtons and D is displacement vector in meters.F.D = - FDcos(Angle) is the Work or scalar energy and FxD=FDsin(Angle) is the Torque or vector energy. If the angle between the force and displacement is 90 degrees there is only torque; if the angle is a zero degrees there is only work or scalar energy ; if the angle is not a multiple of these two angles there is both scalar and vector energy; work and torque. E.g FD= -Fdcos(45) + Fd sin(45) gives work and torque.
Because any angle increased by k*2pi radians (= k*360 degrees) where k is an integer, is, effectively, the same angle. This implies that f(x + 2kpi) = f(x) for any angle x and any trig function f. This gives f a maximum period of 2pi radians.
I don't think it's a special name, but it looks similar to the definition of torque. To be precise, torque is the product of the force, the distance from the axis of rotation, and the since of the angle.
The torque developed by the armature of a DC motor can be expressed as: T = k * Ia * Φ where T is the torque, k is a constant factor, Ia is the armature current, and Φ is the magnetic flux in the motor.
The rotational work equation is rFsin, where represents torque, r is the distance from the axis of rotation to the point where the force is applied, F is the magnitude of the force, and is the angle between the force and the direction of rotation. This equation is used to calculate the work done in a rotational system by multiplying the torque by the angle through which the object rotates.
the name of an f angle is a corresponding angle
Torque=.2*F*Bolt Maj. Dim. F=axial force