This is easier to solve by looking at the reverse problem, what is the probability of the sum being 11 or more. Out of the 6*6 = 36 outcomes, three (5,6), (6,5) and (6,6) satisfy this event. So the probability of getting a sum of 11 or more is 3/36. So the probability of less than 11 is 1-Pr(>=11) = 1 - 3/36 = 33/36 = 11/12 or 0.91667
The probability is 1, if the dice are rolled often enough.
The probability is 1, if the dice are rolled often enough.
Assuming these are regular dice, the probability is 1.
The probability to get a 12, with two dice, is 1/36.
It is 15/36.
The probability is 1, if the dice are rolled often enough.
The probability is 1, if the dice are rolled often enough.
Assuming these are regular dice, the probability is 1.
The probability to get a 12, with two dice, is 1/36.
It is 1/6.
It is 15/36.
1/12
The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.The answer depends on how many dice are rolled. With 12 or more dice, the answer is 0.
35 in 36, or about 0.9722
1/6 because the other numbers don't affect the probability
1/3 or 4/12
you would have a one third chance :0)