Wiki User
∙ 11y ago1/9
Wiki User
∙ 11y agoProb(Sum = 5) = 1/9
21/36 or 7/12 or 58.33...%
The probability is 1, if the dice are rolled often enough.
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
Assuming these are regular dice, the probability is 1.
It's1/12
Prob(Sum = 5) = 1/9
If you rolled 2 fair dice, the probability of having a sum of 6 is 5 over 36
21/36 or 7/12 or 58.33...%
7
The probability that the sum of the numbers rolled is either even or a multiple of 5 is 11/18.
The probability is 1, if the dice are rolled often enough.
If the dice are fair then it is 5/36.
It is 1/9.
3
If two dice are rolled, the probability that the sum of observed values is equal to 13 is zero. The sum of two dice can only lie between 2 and 12, inclusive.
Assuming these are regular dice, the probability is 1.