Since every full pack has four aces, there would be eight aces in two packs. You would have a very good chance of drawing one or more aces.
[original answer] four in 52! ==== The question is not fully stated, but I assume what is being asked is "What are the chances of pulling all four aces out of 52 cards when four cards are drawn". The answer is 1 / 270725 = 0.00000369 = 0.000369%. Approximately four out of one million. The chances are (4*3*2*1) / (52*51*50*49) = 24 / 649700 = 1 / 270725. That is, on the first draw there is a 4/52 chance of drawing one of the four aces out of the full pack; In the 48 out of 52 cases where an ace isn't drawn, "you lose". In the 4/52 cases where an ace is drawn first, there is a 3/51 chance of drawing one of the remaining three aces from the remaining 51 cards. If that happens, there is a 2/50 chance of drawing one of the remaining two aces from the remaining 50 cards; and then a 1/49 chance of drawing the last ace out of the remaining 49 cards. [ If the question is "What are the chances of pulling any of the aces out of 52 cards in one draw" then "four in 52" is correct. ]
It is 8/52 or 2/13
(13*2+2)/52=0.53846
In a full deck of 52 cards your chances are one in thirteen. The same goes for every other card as well not just jacks.
4/52, as there are four aces, and fifty-two cards.
[original answer] four in 52! ==== The question is not fully stated, but I assume what is being asked is "What are the chances of pulling all four aces out of 52 cards when four cards are drawn". The answer is 1 / 270725 = 0.00000369 = 0.000369%. Approximately four out of one million. The chances are (4*3*2*1) / (52*51*50*49) = 24 / 649700 = 1 / 270725. That is, on the first draw there is a 4/52 chance of drawing one of the four aces out of the full pack; In the 48 out of 52 cases where an ace isn't drawn, "you lose". In the 4/52 cases where an ace is drawn first, there is a 3/51 chance of drawing one of the remaining three aces from the remaining 51 cards. If that happens, there is a 2/50 chance of drawing one of the remaining two aces from the remaining 50 cards; and then a 1/49 chance of drawing the last ace out of the remaining 49 cards. [ If the question is "What are the chances of pulling any of the aces out of 52 cards in one draw" then "four in 52" is correct. ]
An easy way to tell if a pack of Pokemon cards contains a full art card is to open it.
Im from India and they sell fake pokemon cards so dont buy.. i have buy 4 noble victries packs i got rashiram full art in all 4 packs which are not from this set.....and if u are a big pokemon cards come to my house and trade...I HaVE MaNY aWSOME CaRDS
The probability is approx 0.09. This assumes that J and K are not prime numbers.
It is 20/52 or 5/13.
(13*2+2)/52=0.53846
It is 8/52 or 2/13
In a full deck of 52 cards your chances are one in thirteen. The same goes for every other card as well not just jacks.
a drawing full of different colors how do you call it
4/52, as there are four aces, and fifty-two cards.
There are 52 cards in a pack of playing cards (excluding jokers). The chance of drawing at random a black card from a full pack of cards is 1/2, or 0.5. There are now 51 cards in the pack, two of which are red kings. The probability of drawing a red king from this pack is 2/51. 0.5 x 2/51 = 0.01960784 So, the probability is approximately 0.0196, or 1.96%.
30