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When two terminals of 4.5 Voltage battery are connected by 100 meters long wire. the current in the wire is 50mA what will be the current from the battery when the wire is shortened 50 meters?
Wiki User
∙ 12y ago
-- The resistance of the wire is proportional to its length.
-- When the length is reduced by 1/2 , the resistance is also reduced by 1/2 .
-- Reducing the resistance across the battery by 1/2 causes the current to double.
-- The new current is 100 mA.
(Assumes zero internal resistance in the battery, and that the 4.5 volts doesn't 'sag'.)
Wiki User
∙ 12y ago
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The voltage (V) between its terminals. ~Gabby
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