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-- The resistance of the wire is proportional to its length.

-- When the length is reduced by 1/2 , the resistance is also reduced by 1/2 .

-- Reducing the resistance across the battery by 1/2 causes the current to double.

-- The new current is 100 mA.

(Assumes zero internal resistance in the battery, and that the 4.5 volts doesn't 'sag'.)

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