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The number is 19.

Q: When you divide my number by 5 the remainder is 4 my number has two digits and both digits are odd the sum of the digits is ten?

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64

64.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

The number is 19.

19.

Starting at the end of the sentence, logically...There only four possible combinations for even counting numbers to add together to make 10:2 + 84 + 66 + 48 + 264 is the only number divisible by 5 with a remainder of 4...

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64

64.000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

64

The number is 19.

19.

19.

Starting at the end of the sentence, logically...There only four possible combinations for even counting numbers to add together to make 10:2 + 84 + 66 + 48 + 264 is the only number divisible by 5 with a remainder of 4...

Any number greater than 199 will divide into both zero times and leave a remainder (of the original number); there is no upper limit to the numbers greater than 199. -------------------------------- The largest number to divide into both and leave the SAME remainder is 56 (leaving a remainder of 31 in both cases).

Take the question apart, one step at a time. The remainder, when the number is divided by 5, is 4. That means that the ones digit is either 4 or 9. However, you know that both digits are odd, which means it has to be 9. The sum of the digits is 10, so the tens digit has to be 1. Your number is 19.

1 and 2 can each divide into both 6 and 8, with no remainder.

19

1 and 13 will both divide 26 and 39 without remainder.