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Q: When you divide the numbers by 7 its quotient is also 7 and its remainder is 3?

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There are no such numbers. Any number can be divided by SOME number without a remainder. For a start, you can divide any number except zero by itself, without a remainder. You can also divide any number by 1 - also, without a remainder.

x/6 = 6 and 4/6 x = 36 plus 24/6 x = 36 plus 4 x = 40

dividend / divisor = quotient Also, the remainder is whatever is left over.

Yes.

First write a program to generate the prime number. After one prime number was generated, divide the big int number by the prime number. If the remainder is zero then quotient is the second prime number ( also it is important to check whether the quotient is prime number or not because sometimes you will get wrong answer). Repeat the process until you get the result.

A division is a dividend divided by the divisor to give the quotient; this is written as:quotient = dividend ÷ divisorA division can also be expressed as the divisor divided into a dividend to give the quotient; this is written as:................. quotient.............. ------------divisor | dividendThe quotient can be just the whole part of the result of the division, in which case there may also be a remainder.

75 ends (least significant digit) in 5 which is an odd number, hence the entire number 75 is odd. Also if you divide 75 by 2 you get a quotient of 37 and a remainder of 1. When a number is divided by 2 and you do not get a remainder of 0, the number is odd, otherwise it is even.

Yes, unless you divide the number by itself, then the answer would be one. Also, you can divide it by one, and the answer would be that number.

To calculate the quotient of 9 you may just need to divide by 3 so you can get the quotient of 3. However you may also want the general factors of nine which are: 1,3,9.

factors or divisors are numbers that divide a number with no remainder. So 9 is a factor of 36 but 9 is also a factor of itself since 9 divided by 9=1 with no remainder. So the answer is 9

11.5

If we insist on the condition that all the numbers must be integers... The only way this can happen is if the quotient and one of the other numbers are negative. For example, if the original numbers are -4 and 2, then their sum is -2, and the quotient of -4 divided by 2 is also -2. I believe that's the only integer example of a set of numbers satisfying that criterion.

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